A train passes a standing man in 10 seconds and a platform 300 meters long in 25 seconds. Find the length of the train. MCQ with Answer and Explanation

A train passes a standing man in 10 seconds and a platform 300 meters long in 25 seconds. Find the length of the train.
A. 150 meters
B. 200 meters
C. 250 meters
D. 300 meters
Answer: Option A
Solution (By JKSSB Mock Tests)
The train takes 25 - 10 = 15 seconds to cover the length of the platform. Speed of the train = 300 / 15 = 20 m/s. Length of the train = Speed * Time to cross the man = 20 * 10 = 150 meters.

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Practice More Time Speed and Distance Questions

Question #1
Walking at 3/4 of his usual speed, a man is 20 minutes late to his office. Find his usual time to reach the office.
A. 50 minutes
B. 70 minutes
C. 60 minutes
D. 80 minutes

Correct Answer: Option C


Explanation:
New Speed = 3/4 of usual speed, so New Time = 4/3 of usual time. Change in time = 4/3 * T - T = 1/3 * T = 20 minutes. Usual time T = 60 minutes.

This question belongs to: Maths Time Speed and Distance
Question #2
A man wins a race of 100 meters over another man by 10 meters or 2 seconds. Find the time taken by the winner to complete the race.
A. 18 seconds
B. 20 seconds
C. 22 seconds
D. 16 seconds

Correct Answer: Option A


Explanation:
The second man covers 10 meters in 2 seconds, so his speed = 10 / 2 = 5 m/s. Total time taken by second man to complete 100m = 100 / 5 = 20 seconds. Since the winner beats him by 2 seconds, winner's time = 20 - 2 = 18 seconds.

This question belongs to: Maths Time Speed and Distance
Question #3
A transport van tracks from terminal X to Y at 40 km/h and handles the return trip route back to X at 60 km/h. What is the average speed recorded across the full round journey?
A. 48 km/h
B. 46 km/h
C. 52 km/h
D. 50 km/h

Correct Answer: Option A


Explanation:
Average Speed across course = 2xy / (x + y) = (2 * 40 * 60) / (40 + 60) = 4800 / 100 = 48 km/h.

This question belongs to: Maths Time Speed and Distance