A train passes a standing man in 6 seconds and a 210-meter long platform in 16 seconds. Find the speed of the train. MCQ with Answer and Explanation

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A train passes a standing man in 6 seconds and a 210-meter long platform in 16 seconds. Find the speed of the train.

A. 75.6 km/h

B. 80 km/h

C. 72 km/h

D. 54 km/h

Answer: Option A

Solution (By JKSSB Mock Tests)

Let length of train be L. Speed = L/6. Also, Speed = (L + 210)/16. Equating them: L/6 = (L+210)/16 => 16L = 6L + 1260 => 10L = 1260 => L = 126 meters. Speed = 126 / 6 = 21 m/s. Speed in km/h = 21 * (18/5) = 378 / 5 = 75.6 km/h.

This question belongs to: Maths Time Speed and Distance

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Question #1

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The speed of two express locomotives are in the ratio 5 : 6. If the second locomotive maps 480 km in 4 hours, find the speed of the first locomotive.

A. 110 km/h

B. 100 km/h

C. 120 km/h

D. 90 km/h

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Correct Answer: Option B

Explanation:
Speed of the second locomotive = 480 / 4 = 120 km/h. Ratio is 5:6, so 6 parts = 120 km/h => 1 part = 20 km/h. Speed of the first locomotive = 5 parts = 5 * 20 = 100 km/h.

This question belongs to: Maths Time Speed and Distance

Question #2

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Walking at 5/7 of his usual speed, a man reaches his destination 24 minutes late. What is his usual time to reach the destination?

A. 75 minutes

B. 50 minutes

C. 80 minutes

D. 60 minutes

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Correct Answer: Option D

Explanation:
New speed = 5/7 of usual speed => New time = 7/5 of usual time. Difference = 2/5 of usual time = 24 minutes. 1/5 of usual time = 12 minutes => Usual time = 60 minutes.

This question belongs to: Maths Time Speed and Distance