A train passes a standing passenger in 8 seconds and crosses a 180-meter long platform in 17 seconds. Find the speed of the train. MCQ with Answer and Explanation

A train passes a standing passenger in 8 seconds and crosses a 180-meter long platform in 17 seconds. Find the speed of the train.
A. 18 m/s
B. 22 m/s
C. 24 m/s
D. 20 m/s
Answer: Option D
Solution (By JKSSB Mock Tests)
Time taken to pass the platform alone = 17 - 8 = 9 seconds. Speed of train = 180 / 9 = 20 m/s.

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Practice More Time Speed and Distance Questions

Question #1
A person covers a certain distance at a certain speed. If he reduces his speed by 20%, he takes 15 minutes more to cover the same distance. Find his usual time.
A. 60 minutes
B. 80 minutes
C. 75 minutes
D. 50 minutes

Correct Answer: Option A


Explanation:
New Speed = 0.8 * Usual Speed. Since distance is constant, New Time = Usual Time / 0.8 = 1.25 * Usual Time. Increase in time = 0.25 * Usual Time = 15 minutes. Usual Time = 15 / 0.25 = 60 minutes.

This question belongs to: Maths Time Speed and Distance
Question #2
Excluding stoppages, the speed of a regional transit bus is 48 km/h and including stoppages it is 40 km/h. For how many minutes does the bus stop per hour?
A. 8 minutes
B. 15 minutes
C. 10 minutes
D. 12 minutes

Correct Answer: Option C


Explanation:
Stoppage time per hour = (48 - 40) / 48 = 8 / 48 = 1/6 hour. In minutes = (1/6) * 60 = 10 minutes.

This question belongs to: Maths Time Speed and Distance
Question #3
A wheel has a radius of 42 cm. How many revolutions must it make to cover a distance of 132 meters?
A. 70 revolutions
B. 40 revolutions
C. 60 revolutions
D. 50 revolutions

Correct Answer: Option D


Explanation:
Circumference of the wheel = 2 * (22/7) * 42 = 264 cm = 2.64 meters. Total distance = 132 meters. Number of revolutions = 132 / 2.64 = 50 revolutions.

This question belongs to: Maths Time Speed and Distance