A train passes a static observer in 8 seconds and a platform 120 meters long in 14 seconds. Find the length of the train. MCQ with Answer and Explanation

A train passes a static observer in 8 seconds and a platform 120 meters long in 14 seconds. Find the length of the train.
A. 200 meters
B. 160 meters
C. 180 meters
D. 150 meters
Answer: Option B
Solution (By JKSSB Mock Tests)
Time to cross the platform alone = 14 - 8 = 6 seconds. Speed of train = 120 / 6 = 20 m/s. Length of train = Speed * Time to pass observer = 20 * 8 = 160 meters.

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Practice More Time Speed and Distance Questions

Question #1
A car travels from A to B at 40 km/h and returns to A at 60 km/h. What is the average speed for the round journey?
A. 50 km/h
B. 46 km/h
C. 52 km/h
D. 48 km/h

Correct Answer: Option D


Explanation:
Average Speed = 2xy / (x + y) = (2 * 40 * 60) / (40 + 60) = 4800 / 100 = 48 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
Walking at 3/4 of his normal speed, a person is 10 minutes late to his destination. What is his normal time?
A. 25 minutes
B. 30 minutes
C. 35 minutes
D. 40 minutes

Correct Answer: Option B


Explanation:
New speed = 3/4 of normal speed => New time = 4/3 of normal time. Difference = 1/3 of normal time = 10 minutes. Normal time = 10 * 3 = 30 minutes.

This question belongs to: Maths Time Speed and Distance
Question #3
A person covers 1/3 of a distance at 20 km/h, 1/3 at 30 km/h and the last 1/3 at 60 km/h. Find the average speed.
A. 30 km/h
B. 35 km/h
C. 32 km/h
D. 28 km/h

Correct Answer: Option A


Explanation:
Let each third of the distance be 60 km. Total distance = 180 km. Total time taken = 60/20 + 60/30 + 60/60 = 3 + 2 + 1 = 6 hours. Average speed = 180 / 6 = 30 km/h.

This question belongs to: Maths Time Speed and Distance