A vehicle covers a lap distance of 450 km at a uniform speed. If its velocity is cut by 15 km/h, the trip maps 1.5 hours longer. Find the original speed. MCQ with Answer and Explanation
A vehicle covers a lap distance of 450 km at a uniform speed. If its velocity is cut by 15 km/h, the trip maps 1.5 hours longer. Find the original speed.
A. 75 km/h
B. 80 km/h
C. 90 km/h
D. 60 km/h
Answer: Option A
Solution (By JKSSB Mock Tests)
Let original speed be s. 450/(s-15) - 450/s = 1.5 => 300/(s-15) - 300/s = 1 => 300(15) = s(s-15) => 4500 = s(s-15). Solving s^2 - 15s - 4500 = 0 gives (s-75)(s+60) = 0. Baseline speed = 75 km/h.
A runner tracks a circular field loop course of radius 70 meters. If his speed registers at 20 m/s, find the total loop rounds completed by him in 2 minutes 12 seconds.
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