A wire of resistance 6 Ω is stretched to thrice its original length. New resistance is MCQ with Answer and Explanation

A wire of resistance 6 Ω is stretched to thrice its original length. New resistance is
A. 54 Ω
B. 36 Ω
C. 2 Ω
D. 18 Ω
Answer: Option A
Solution (By JKSSB Mock Tests)
R ∝ L² (volume constant). L'=3L => R' = 3² × 6 = 9×6 = 54 Ω. Generally, R' = n² R for stretching n times. Important concept.

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