According to the Equation of Continuity in fluid dynamics, when water flows through a pipe of varying cross-section, the velocity of the fluid is: MCQ with Answer and Explanation

Question

According to the Equation of Continuity in fluid dynamics, when water flows through a pipe of varying cross-section, the velocity of the fluid is:

A. Inversely proportional to the cross-sectional area.

B. Directly proportional to the square of the cross-sectional area.

C. Directly proportional to the cross-sectional area.

D. Independent of the cross-sectional area.

Answer: Option A

Solution (By JKSSB Mock Tests)

The Equation of Continuity states that for an incompressible, non-viscous fluid in streamlined flow, the mass flow rate is constant. Therefore, A1V1 = A2V2, where A is the area of cross-section and V is the velocity. This means V is inversely proportional to A (V ∝ 1/A). As the pipe narrows, the fluid speeds up.

This question belongs to: Science Physics

Request complete Subject PDF

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Physics Questions

Question #1

Share Report

The time taken by a pendulum to complete one oscillation is called

A. Wavelength

B. Amplitude

C. Frequency

D. Time period

View Answer & Solution Discuss

Get Complete Subject PDF for Science

Correct Answer: Option D

Explanation:
Time period T = 2π√(L/g) for simple pendulum. Frequency = 1/T. Amplitude is max displacement. Wavelength for waves.

This question belongs to: Science Physics

Question #2

Share Report

A particle moves such that its position coordinates (x, y) are given by x = 2t and y = t^2. The equation of its trajectory is:

A. y = x^2 / 2

B. y = x^2 / 4

C. y = 2x^2

D. y = x

View Answer & Solution Discuss

Get Complete Subject PDF for Science

Correct Answer: Option B

Explanation:
The equation of trajectory represents the path of the particle in the x-y plane, eliminating the time variable 't'. Given x = 2t, we can write t = x/2. Substitute this into the y equation: y = t^2 = (x/2)^2 = x^2 / 4. This confirms the particle moves in a parabolic path.

This question belongs to: Science Physics