A car covered a distance of 300 km at a uniform speed. If the baseline speed is lowered by 10 km/h, the trip duration spikes by 1 hour. Find the original speed.
Explanation:
Let original speed be s. 300 / (s - 10) - 300 / s = 1 => 300(10) = s(s - 10) => 3000 = s(s - 10). Solving s^2 - 10s - 3000 = 0 yields (s - 60)(s + 50) = 0. Since speed must be positive, s = 60 km/h.
A man covers 2/3 of a journey at 40 km/h, 1/4 of the journey at 30 km/h and the remainder at 10 km/h. What is his average speed for the entire journey?
Explanation:
Let the total distance be 120 km. First part = (2/3) * 120 = 80 km; Time = 80 / 40 = 2 hours. Second part = (1/4) * 120 = 30 km; Time = 30 / 30 = 1 hour. Remainder = 120 - 80 - 30 = 10 km; Time = 10 / 10 = 1 hour. Total time = 2 + 1 + 1 = 4 hours. Average speed = 120 / 4 = 32 km/h.
No comments yet. Be the first to start the discussion!