Assertion (A): The mass of an atom is concentrated in the nucleus. Reason (R): Protons and neutrons are present inside the nucleus. MCQ with Answer and Explanation

Assertion (A): The mass of an atom is concentrated in the nucleus. Reason (R): Protons and neutrons are present inside the nucleus.
A. Both A and R are true and R is the correct explanation of A.
B. A is false but R is true.
C. A is true but R is false.
D. Both A and R are true but R is NOT the correct explanation of A.
Answer: Option A
Solution (By JKSSB Mock Tests)
The mass of an atom is almost entirely concentrated in its tiny central nucleus. This is because the nucleus contains protons and neutrons, which are much heavier than the extranuclear electrons. Since electrons have negligible mass, R correctly explains why the mass is localized in the nucleus.

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Practice More chemistry Questions

Question #1
In the reaction MnO₂ + 4HCl → MnCl₂ + Cl₂ + 2H₂O, HCl is:
A. Dehydrating agent
B. Catalyst
C. Oxidizing agent
D. Reducing agent

Correct Answer: Option D


Explanation:
HCl is oxidized (Cl⁻ → Cl₂, loss of electrons), so it acts as the reducing agent. MnO₂ is reduced (Mn⁴⁺ → Mn²⁺) and is the oxidizing agent.

This question belongs to: Science chemistry
Question #2
The maximum number of electrons that can be accommodated in the N shell is:
A. 50
B. 18
C. 8
D. 32

Correct Answer: Option D


Explanation:
The maximum number of electrons in a shell is given by the formula 2n², where n is the principal quantum number. For the N shell, n = 4. Thus, maximum electrons = 2(4)² = 2(16) = 32. The K, L, M, and N shells hold 2, 8, 18, and 32 electrons respectively.

This question belongs to: Science chemistry
Question #3
Which of the following reactions is NOT a redox reaction?
A. Zn + CuSO₄ → ZnSO₄ + Cu
B. 2Na + Cl₂ → 2NaCl
C. CH₄ + 2O₂ → CO₂ + 2H₂O
D. CaCO₃ → CaO + CO₂

Correct Answer: Option D


Explanation:
In CaCO₃ decomposition, the oxidation states are: Ca (+2), C (+4), O (-2) in both reactant and products, so no change—not a redox reaction. The others involve changes: Zn(0→+2), Cu(+2→0) in B; Na(0→+1), Cl(0→-1) in C; C(-4→+4), O(0→-2) in D. Redox requires change in oxidation numbers.

This question belongs to: Science chemistry