Gravitational constant G dimensions: MCQ with Answer and Explanation

Gravitational constant G dimensions:
A. [M⁻¹L²T⁻²]
B. [M⁻¹L³T⁻²]
C. [ML³T⁻²]
D. [M⁰L⁰T⁰]
Answer: Option B
Solution (By JKSSB Mock Tests)
F = Gm₁m₂/r² ⇒ G = Fr²/(m₁m₂) = [MLT⁻²][L²]/[M²] = [M⁻¹L³T⁻²]. Memory aid: 'G dimensions: [M⁻¹L³T⁻²]; small value reflects weak gravity'. Dimensional analysis frequently tested in competitive exams.

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