Heat required to convert 1 g of ice at 0°C to water at 0°C is (latent heat 80 cal/g) MCQ with Answer and Explanation

Heat required to convert 1 g of ice at 0°C to water at 0°C is (latent heat 80 cal/g)
A. 80 cal
B. 540 cal
C. 1 cal
D. 100 cal
Answer: Option A
Solution (By JKSSB Mock Tests)
Latent heat of fusion of ice = 80 cal/g. So 1 g needs 80 cal. No temperature change.

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