A man can walk a certain distance in 6 hours and ride back in 2 hours. If he rides both ways, he will save 2 hours. How much time will he take if he walks both ways?
Explanation:
Let W be walking time one way and R be riding time one way. W + R = 6 + 2 = 8 hours (total trip: walk one way, ride back). If he rides both ways, total time is 2R. He saves 2 hours, so 2R = 8 - 2 = 6 hours => R = 3 hours. From W + R = 8, W = 5 hours. Walking both ways takes 2W = 10 hours.
Explanation:
New speed = 5/7 of usual speed => New time = 7/5 of usual time. Difference = 2/5 of usual time = 24 minutes. 1/5 of usual time = 12 minutes => Usual time = 60 minutes.
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