If the momentum of a body is increased by 50%, what will be the percentage increase in its kinetic energy? MCQ with Answer and Explanation

Explanation:
For spring-mass system undergoing SHM, time period T = 2π√(M/k), derived from F = -kx = Ma ⇒ a = -(k/M)x, so ω² = k/M, T=2π/ω=2π√(M/k). Option B has inverse ratio; C misses factor 2; D is for pendulum. Memory tip: 'Spring: T ∝ √(M/k); Pendulum: T ∝ √(l/g)'. This standard formula is frequently tested in oscillations sections of competitive exams. Always verify dimensions: √(kg / (N/m)) = √(kg·m/N) = √(s²) = s, correct for time period.

Explanation:
Leading zeros not significant. '450' has three digits, but the trailing zero after decimal is significant (4,5,0). So 3 significant figures. 0.00450 is 3 SF.

Explanation:
Resonance: X_L = X_C ⇒ they cancel ⇒ Z = R (minimum). Current maximum at resonance. Memory tip: 'Series resonance: Z_min = R; parallel: Z_max'. AC circuit concept frequently tested in competitive exams.