If the numerator of a fraction is increased by 50% and the denominator is decreased by 25%, it becomes 5/8. Find the original fraction. MCQ with Answer and Explanation

Question

If the numerator of a fraction is increased by 50% and the denominator is decreased by 25%, it becomes 5/8. Find the original fraction.

A. 3/8

B. 5/16

C. 5/12

D. 7/16

Answer: Option B

Solution (By JKSSB Mock Tests)

(1.5N)/(0.75D) = 2N/D = 5/8 → N/D = 5/16.

This question belongs to: Maths Percentage

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Question #1

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In a mixture, the ratio of copper to zinc is 5:3. If 20% of the mixture is removed, what percentage of the remaining mixture is copper?

A. 50%

B. 62.5%

C. 60%

D. 70%

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Correct Answer: Option B

Explanation:
Removing part of the mixture does not change the ratio. Copper proportion = 5 / (5+3) = 5/8. Percentage = (5/8) * 100 = 62.5%.

This question belongs to: Maths Percentage

Question #2

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Price of petrol increased by 25%. To keep expenditure same, consumption must reduce by:

A. 15%

B. 20%

C. 25%

D. 10%

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Correct Answer: Option B

Explanation:
Reduction % = (25/125)×100 = 20%.

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Question #3

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A number is such that 25% of it is 5 more than 20% of it. Find the number.

A. 100

B. 90

C. 120

D. 80

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Correct Answer: Option A

Explanation:
0.25x = 0.2x + 5 → 0.05x = 5 → x = 100.

This question belongs to: Maths Percentage

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