If the random error in measurement of radius of a sphere is 2%, the error in volume is MCQ with Answer and Explanation

If the random error in measurement of radius of a sphere is 2%, the error in volume is
A. 6%
B. 2%
C. 8%
D. 4%
Answer: Option A
Solution (By JKSSB Mock Tests)
Volume V = (4/3)πr³. Fractional error ΔV/V = 3 Δr/r. Percentage error = 3 × 2% = 6%. Important for error analysis in competitive exams.

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