In a 100-meter race, A can beat B by 15 meters and C by 28 meters. In a race of 85 meters, by how many meters can B beat C? MCQ with Answer and Explanation
In a 100-meter race, A can beat B by 15 meters and C by 28 meters. In a race of 85 meters, by how many meters can B beat C?
A. 13 meters
B. 14 meters
C. 12 meters
D. 15 meters
Answer: Option A
Solution (By JKSSB Mock Tests)
When A covers 100m, B covers 85m and C covers 72m. This means in a distance where B covers 85 meters, C covers 72 meters. Therefore, B beats C by 85 - 72 = 13 meters.
Explanation:
New speed = 7/9 of usual speed => New time = 9/7 of usual time. Difference = 2/7 of usual time = 20 minutes. Therefore, 1/7 of usual time = 10 minutes => Usual time = 70 minutes.
A hound pursues a fox that is initially 150 meters ahead. The fox flies at 30 km/h and the hound targets at 36 km/h. Find the total distance the fox runs before capture.
A car covered a distance of 200 km at a uniform speed. If the speed is reduced by 10 km/h, the time taken increases by 1 hour. Find the original speed.
Explanation:
Let original speed be s. 200 / (s - 10) - 200 / s = 1 => 200(s - s + 10) = s(s - 10) => 2000 = s(s - 10). Solving s^2 - 10s - 2000 = 0 gives (s - 50)(s + 40) = 0. Since speed is positive, s = 50 km/h.
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