In a 500-meter race, the ratio of speeds of two runners A and B is 3:4. A has a start of 140 meters. Who wins the race and by how many meters? MCQ with Answer and Explanation
In a 500-meter race, the ratio of speeds of two runners A and B is 3:4. A has a start of 140 meters. Who wins the race and by how many meters?
A. A wins by 40m
B. A wins by 20m
C. B wins by 40m
D. B wins by 20m
Answer: Option B
Solution (By JKSSB Mock Tests)
Distance for A to run = 500 - 140 = 360 meters. Ratio of speeds A:B = 3:4. Time taken by A to run 360m is proportional to 360 / 3 = 120 units. In the same time, B runs 4 * 120 = 480 meters. B needs 500m to win but only reaches 480m. Thus, A wins, and B is 500 - 480 = 20 meters behind. A wins by 20 meters.
Explanation:
Speed of runner-up = 100 / 12.5 = 8 m/s. When the winner crosses the finish line at 12 seconds, the distance covered by runner-up = 8 * 12 = 96 meters. Distance by which he lost = 100 - 96 = 5 meters.
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