In a moderately skewed distribution, the empirical relationship is Mode ≈ 3×Median - 2×Mean. If Mean=60 and Median=58, Mode is approximately: MCQ with Answer and Explanation

Question

In a moderately skewed distribution, the empirical relationship is Mode ≈ 3×Median - 2×Mean. If Mean=60 and Median=58, Mode is approximately:

A. 54

B. 52

C. 58

D. 56

Answer: Option A

Solution (By JKSSB Mock Tests)

Mode ≈ 3×58 - 2×60 = 174 - 120 = 54. This approximation, attributed to Pearson, holds for unimodal distributions with moderate skewness.

This question belongs to: Accountancy and Statistics Statistics

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Question #1

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Attributes that can only be classified into two mutually exclusive categories (e.g., Male/Female) are termed:

A. Continuous variables

B. Dichotomous attributes

C. Quantitative variables

D. Manifold attributes

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Correct Answer: Option B

Explanation:
Dichotomous classification divides data into exactly two contrasting categories based on the presence or absence of a trait.

This question belongs to: Accountancy and Statistics Statistics

Question #2

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If events A and B are independent, which of the following must be true?

A. P(A|B) = P(A)

B. P(A) + P(B) = 1

C. P(A ∩ B) = 0

D. A and B are mutually exclusive

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Correct Answer: Option A

Explanation:
Independence means knowledge of B does not affect A's probability, so P(A|B) = P(A); this is equivalent to P(A∩B)=P(A)P(B).

This question belongs to: Accountancy and Statistics Statistics

Question #3

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The combined mean of two groups with n₁=20, mean₁=50 and n₂=30, mean₂=60 is:

A. 55

B. 54

C. 56

D. 57

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Correct Answer: Option C

Explanation:
Combined mean = (20×50 + 30×60) / (20+30) = (1000+1800)/50 = 2800/50 = 56.

This question belongs to: Accountancy and Statistics Statistics

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