In geometric optics, the power of a lens is defined as the reciprocal of its: MCQ with Answer and Explanation

In geometric optics, the power of a lens is defined as the reciprocal of its:
A. Magnification
B. Refractive index
C. Radius of curvature
D. Focal length in meters
Answer: Option D
Solution (By JKSSB Mock Tests)
The power (P) of a lens indicates its converging or diverging ability. It is mathematically defined as the reciprocal of the focal length (f), provided the focal length is measured in meters. The formula is P = 1 / f(in meters). The SI unit of power for a lens is the Diopter (D). A focal length of 0.5m gives a power of 2D.

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Practice More Physics Questions

Question #1
A 100 W bulb operates at 200 V. Its resistance is
A. 100 Ω
B. 400 Ω
C. 200 Ω
D. 50 Ω

Correct Answer: Option B


Explanation:
Power P = V²/R => R = V²/P = 200²/100 = 40000/100 = 400 Ω. Also current I = P/V = 0.5 A, R = V/I = 200/0.5 = 400 Ω. Use P = V²/R for direct calculation.

This question belongs to: Science Physics
Question #2
A bar magnet is cut into two equal parts transversely. The pole strength of each piece becomes
A. Double
B. Half
C. Zero
D. Same

Correct Answer: Option D


Explanation:
Pole strength is a property of the magnet; when cut transversely, each piece still has both north and south poles with same pole strength as original. Magnetic moment becomes half because length halves. Each is a complete magnet.

This question belongs to: Science Physics
Question #3
The escape velocity from a planet depends on:
A. Both mass and radius of the planet
B. Mass of the escaping body
C. Temperature of the planet
D. Radius of the planet only

Correct Answer: Option A


Explanation:
Escape velocity v_e = √(2GM/R), where M is planet mass, R its radius. Thus v_e depends on both M and R. It is independent of the escaping body's mass (as gravitational and inertial mass cancel). Memory tip: 'v_e ∝ √(M/R); larger M or smaller R ⇒ higher escape velocity'. This gravitation formula application is frequently tested in competitive exams. Always recall that escape velocity is a property of the planet, not the projectile. This problem assesses understanding of gravitational potential energy concepts.

This question belongs to: Science Physics