Time Speed and Distance MCQs

Maths

Time Speed and Distance MCQs

Practice Time, Speed and Distance MCQs with answers and detailed solutions. Learn train problems, boats and streams, relative speed, average speed, races, journeys and advanced quantitative aptitude questions for competitive examinations.

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Question #41
A man walks a certain distance at 5 km/h and runs back at 15 km/h. What is his average speed for the entire journey?
A. 10 km/h
B. 8 km/h
C. 7.5 km/h
D. 9 km/h

Correct Answer: Option C


Explanation:
Average Speed = (2 * 5 * 15) / (5 + 15) = 150 / 20 = 7.5 km/h.

This question belongs to: Maths Time Speed and Distance
Question #42
Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train is 120 meters, in what time will they cross each other traveling in opposite directions?
A. 12 seconds
B. 15 seconds
C. 14 seconds
D. 10 seconds

Correct Answer: Option A


Explanation:
Speed of first train = 120 / 10 = 12 m/s. Speed of second train = 120 / 15 = 8 m/s. Total distance to cross each other = 120 + 120 = 240 meters. Relative speed in opposite directions = 12 + 8 = 20 m/s. Time = 240 / 20 = 12 seconds.

This question belongs to: Maths Time Speed and Distance
Question #43
A man rides a bicycle at 12 km/h from his house to his school and reaches 5 minutes late. Next day he increases his speed to 15 km/h and reaches 5 minutes early. Find the distance between his house and school.
A. 8 km
B. 12 km
C. 15 km
D. 10 km

Correct Answer: Option D


Explanation:
Time difference = 5 - (-5) = 10 minutes = 1/6 hour. Let distance be d. d/12 - d/15 = 1/6 => (5d - 4d)/60 = 1/6 => d/60 = 1/6 => d = 10 km.

This question belongs to: Maths Time Speed and Distance
Question #44
A thief steals a car at 2:30 PM and drives it at 60 km/h. The theft is discovered at 3:00 PM and the owner sets off in another car at 75 km/h. When will he overtake the thief?
A. 4:30 PM
B. 5:00 PM
C. 4:45 PM
D. 5:15 PM

Correct Answer: Option B


Explanation:
By 3:00 PM, the thief has driven for 30 minutes (0.5 hours) and covered 60 * 0.5 = 30 km. Relative speed of owner = 75 - 60 = 15 km/h. Time to catch thief = 30 / 15 = 2 hours. Overtaking time = 3:00 PM + 2 hours = 5:00 PM.

This question belongs to: Maths Time Speed and Distance
Question #45
A train running at 54 km/h takes 20 seconds to pass a bridge. Next, it passes a man walking at 6 km/h in the same direction in 12 seconds. Find the length of the bridge.
A. 140 meters
B. 160 meters
C. 150 meters
D. 120 meters

Correct Answer: Option A


Explanation:
Speed of train = 54 km/h = 15 m/s. Speed of man = 6 km/h = 5/3 m/s. Relative speed = 15 - 5/3 = 40/3 m/s. Length of train = Relative speed * time = (40/3) * 12 = 160 meters. To pass bridge: Total distance = Length of train + Length of bridge = 15 m/s * 20 seconds = 300 meters. Length of bridge = 300 - 160 = 140 meters.

This question belongs to: Maths Time Speed and Distance
Question #46
A person covers a certain distance at a certain speed. If he reduces his speed by 20%, he takes 15 minutes more to cover the same distance. Find his usual time.
A. 80 minutes
B. 75 minutes
C. 50 minutes
D. 60 minutes

Correct Answer: Option D


Explanation:
New Speed = 0.8 * Usual Speed. Since distance is constant, New Time = Usual Time / 0.8 = 1.25 * Usual Time. Increase in time = 0.25 * Usual Time = 15 minutes. Usual Time = 15 / 0.25 = 60 minutes.

This question belongs to: Maths Time Speed and Distance
Question #47
In a 1000m race, A beats B by 100m and B beats C by 100m. By how many meters does A beat C in the same race?
A. 180m
B. 190m
C. 200m
D. 210m

Correct Answer: Option B


Explanation:
When A covers 1000m, B covers 900m. When B covers 1000m, C covers 900m. So when B covers 900m, C covers 900 * (900/1000) = 810m. Therefore, when A covers 1000m, C covers 810m. A beats C by 1000 - 810 = 190m.

This question belongs to: Maths Time Speed and Distance
Question #48
A man can row 8 km/h in still water. If the river is running at 4 km/h, it takes him 6 hours to row to a place and back. How far is the place?
A. 20 km
B. 18 km
C. 24 km
D. 16 km

Correct Answer: Option B


Explanation:
Downstream speed = 8 + 4 = 12 km/h. Upstream speed = 8 - 4 = 4 km/h. Let distance be d. d/12 + d/4 = 6 => 4d/12 = 6 => d/3 = 6 => d = 18 km.

This question belongs to: Maths Time Speed and Distance
Question #49
A train 110 meters long is running at a speed of 58 km/h. How much time will it take to pass a man running at 4 km/h in the opposite direction?
A. 6 seconds
B. 6.38 seconds
C. 7 seconds
D. 7.5 seconds

Correct Answer: Option B


Explanation:
Relative speed = 58 + 4 = 62 km/h = 62 * (5/18) = 155/9 m/s. Time = Distance / Speed = 110 / (155/9) = 110 * 9 / 155 = 990 / 155 = 6.38 seconds.

This question belongs to: Maths Time Speed and Distance
Question #50
The ratio of speeds of a car, a train and a bus is 5 : 9 : 4. The average speed of the car, the train and the bus together is 60 km/h. What is the average speed of the car and the bus together?
A. 54 km/h
B. 45 km/h
C. 50 km/h
D. 60 km/h

Correct Answer: Option B


Explanation:
Let the speeds be 5x, 9x, and 4x. Average speed of all three = (5x + 9x + 4x) / 3 = 18x / 3 = 6x = 60 km/h => x = 10. Speed of car = 50 km/h, speed of bus = 40 km/h. Average speed of car and bus = (50 + 40) / 2 = 45 km/h.

This question belongs to: Maths Time Speed and Distance
Question #51
A car covers four successive 3 km stretches at speeds of 10 km/h, 20 km/h, 30 km/h and 60 km/h respectively. Its average speed for this distance is:
A. 20 km/h
B. 25 km/h
C. 30 km/h
D. 24 km/h

Correct Answer: Option A


Explanation:
Total distance = 4 * 3 = 12 km. Total time = 3/10 + 3/20 + 3/30 + 3/60 = (18 + 9 + 6 + 3)/60 = 36/60 = 0.6 hours. Average speed = 12 / 0.6 = 20 km/h.

This question belongs to: Maths Time Speed and Distance
Question #52
A man covers 1/3rd of his journey at 20 km/h and the remaining 2/3rd at 40 km/h. If the total distance is 120 km, find the total time taken for the journey.
A. 5 hours
B. 4.5 hours
C. 3.5 hours
D. 4 hours

Correct Answer: Option D


Explanation:
First part distance = 120 / 3 = 40 km. Time1 = 40 / 20 = 2 hours. Remaining distance = 80 km. Time2 = 80 / 40 = 2 hours. Total time = 2 + 2 = 4 hours.

This question belongs to: Maths Time Speed and Distance
Question #53
A person wins a 100m race by completing it in 12 seconds. The runner-up takes 12.5 seconds. By how many meters did the winner beat the runner-up?
A. 4 meters
B. 6 meters
C. 8 meters
D. 5 meters

Correct Answer: Option D


Explanation:
Speed of runner-up = 100 / 12.5 = 8 m/s. When the winner crosses the finish line at 12 seconds, the distance covered by runner-up = 8 * 12 = 96 meters. Distance by which he lost = 100 - 96 = 5 meters.

This question belongs to: Maths Time Speed and Distance
Question #54
Two points P and Q are 240 km apart. Train A starts from P towards Q at 60 km/h at 9:00 AM. Train B starts from Q towards P at 80 km/h at 10:00 AM. At what time will they meet?
A. 11:30 AM
B. 11:45 AM
C. 11:00 AM
D. 11:17 AM

Correct Answer: Option D


Explanation:
By 10:00 AM, Train A covers 60 km. Remaining distance = 240 - 60 = 180 km. Relative speed = 60 + 80 = 140 km/h. Time to meet after 10 AM = 180 / 140 = 9/7 hours = 1 hour and 17 minutes. Meeting time is 11:17 AM.

This question belongs to: Maths Time Speed and Distance
Question #55
If a student walks from his house to school at 5 km/h, he is late by 10 minutes. However, if he walks at 6 km/h, he is late by only 2 minutes. Find the distance between his house and school.
A. 4 km
B. 6 km
C. 3 km
D. 5 km

Correct Answer: Option A


Explanation:
Time difference = 10 - 2 = 8 minutes = 8/60 hour = 2/15 hour. Let distance be d. d/5 - d/6 = 2/15 => d/30 = 2/15 => d = 60/15 = 4 km.

This question belongs to: Maths Time Speed and Distance
Question #56
A car travels the first half of a total distance at speed v1 and the second half at speed v2. What is the expression for the average speed of the car?
A. v1*v2 / (v1 + v2)
B. 2 / (v1 + v2)
C. (v1 + v2) / 2
D. 2v1*v2 / (v1 + v2)

Correct Answer: Option D


Explanation:
When equal distances are traveled at speeds v1 and v2, the average speed is the harmonic mean: 2v1*v2 / (v1 + v2).

This question belongs to: Maths Time Speed and Distance
Question #57
A train running at 90 km/h crosses a platform double its length in 36 seconds. What is the length of the platform?
A. 500 meters
B. 750 meters
C. 600 meters
D. 400 meters

Correct Answer: Option C


Explanation:
Speed of train = 90 * (5/18) = 25 m/s. Total distance covered in 36 seconds = 25 * 36 = 900 meters. Let train length be L, so platform length = 2L. L + 2L = 900 => 3L = 900 => L = 300 meters. Platform length = 2L = 600 meters.

This question belongs to: Maths Time Speed and Distance
Question #58
A standard boat covers 12 km upstream in 4 hours and 16 km downstream in 2 hours. What is the speed of the boat in still water?
A. 6.5 km/h
B. 5.5 km/h
C. 6 km/h
D. 7 km/h

Correct Answer: Option B


Explanation:
Upstream speed = 12 / 4 = 3 km/h. Downstream speed = 16 / 2 = 8 km/h. Speed in still water = (Downstream speed + Upstream speed) / 2 = (8 + 3) / 2 = 5.5 km/h.

This question belongs to: Maths Time Speed and Distance
Question #59
A man can walk at 6 km/h. After every kilometer, he takes a rest of 6 minutes. How much time will he take to cover a distance of 18 km?
A. 4 hours 42 minutes
B. 5 hours
C. 4 hours 48 minutes
D. 4 hours 30 minutes

Correct Answer: Option A


Explanation:
Pure walking time = 18 / 6 = 3 hours. Number of rest intervals = 18 - 1 = 17 intervals. Total rest time = 17 * 6 = 102 minutes = 1 hour 42 minutes. Total time = 3 hours + 1 hour 42 minutes = 4 hours 42 minutes.

This question belongs to: Maths Time Speed and Distance
Question #60
Two trains start from stations A and B and travel towards each other at speeds of 50 km/h and 60 km/h respectively. At the time of their meeting, the second train has traveled 120 km more than the first. Find the distance between A and B.
A. 1500 km
B. 1320 km
C. 1200 km
D. 1440 km

Correct Answer: Option B


Explanation:
Let the time they travel before meeting be t hours. Distance difference = 60t - 50t = 10t = 120 km => t = 12 hours. Total distance = (50 + 60) * t = 110 * 12 = 1320 km.

This question belongs to: Maths Time Speed and Distance