A man rides a bicycle at 12 km/h from his house to his school and reaches 5 minutes late. Next day he increases his speed to 15 km/h and reaches 5 minutes early. Find the distance between his house and school. MCQ with Answer and Explanation
A man rides a bicycle at 12 km/h from his house to his school and reaches 5 minutes late. Next day he increases his speed to 15 km/h and reaches 5 minutes early. Find the distance between his house and school.
A. 10 km
B. 8 km
C. 12 km
D. 15 km
Answer: Option A
Solution (By JKSSB Mock Tests)
Time difference = 5 - (-5) = 10 minutes = 1/6 hour. Let distance be d. d/12 - d/15 = 1/6 => (5d - 4d)/60 = 1/6 => d/60 = 1/6 => d = 10 km.
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