The device used to measure electric potential difference is
A. Ammeter
B. Voltmeter
C. Galvanometer
D. Ohmmeter
Answer: Option B
Solution (By JKSSB Mock Tests)
Voltmeter measures potential difference in volts. Connected in parallel, high resistance. Galvanometer detects small current, can be converted to ammeter/voltmeter. Ammeter for current. Ohmmeter for resistance.
Explanation:
Frequency = vibrations per second. 500 vibrations per second. In 2 min = 120 s, total vibrations = 500 × 120 = 60,000. Simple multiplication.
Explanation:
Acceleration a = (v-u)/t = (8-2)/10 = 0.6 m/s². Force F = m×a = 5 × 0.6 = 3 N. Alternatively, impulse = change in momentum = 5×(8-2) = 30 kg m/s, time = 10 s, so average force = 30/10 = 3 N. Always check direction, but magnitude is 3 N.
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