The device used to measure electric potential difference is MCQ with Answer and Explanation

The device used to measure electric potential difference is
A. Ohmmeter
B. Galvanometer
C. Ammeter
D. Voltmeter
Answer: Option D
Solution (By JKSSB Mock Tests)
Voltmeter measures potential difference in volts. Connected in parallel, high resistance. Galvanometer detects small current, can be converted to ammeter/voltmeter. Ammeter for current. Ohmmeter for resistance.

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The electromagnetic waves with highest frequency are
A. Ultraviolet
B. Radio waves
C. X-rays
D. Gamma rays

Correct Answer: Option D


Explanation:
Gamma rays >10¹⁹ Hz, highest.

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Correct Answer: Option D


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The gravitational potential strictly at the center of a solid, uniform Earth of mass M and radius R is:
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Correct Answer: Option C


Explanation:
The gravitational potential V inside a uniform solid sphere at a distance r from the center is V = -GM * (3R^2 - r^2) / (2R^3). At the exact center of the Earth, r = 0. Substituting r = 0 gives V = -GM(3R^2) / 2R^3 = -3GM / 2R. The potential is strictly non-zero and highly negative.

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