The freezing point of mercury is -39°C. It cannot be used in thermometers for temperatures below this because MCQ with Answer and Explanation

The freezing point of mercury is -39°C. It cannot be used in thermometers for temperatures below this because
A. It becomes transparent
B. It expands
C. It freezes
D. It evaporates
Answer: Option C
Solution (By JKSSB Mock Tests)
Below freezing point, mercury solidifies and doesn't work. Alcohol thermometers used for low temps.

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Practice More Physics Questions

Question #1
Heat required to raise 2 kg water from 20°C to 100°C: (c_water = 4200 J/kg·K)
A. 168 kJ
B. 840 kJ
C. 672 kJ
D. 336 kJ

Correct Answer: Option C


Explanation:
Q = mcΔT = 2×4200×(100-20) = 2×4200×80 = 672000 J = 672 kJ. Direct calorimetry formula application. Memory tip: 'Q = mcΔT; ΔT in Celsius or Kelvin same'. Basic numerical testing specific heat concept, frequently appearing in thermodynamics sections of competitive exams.

This question belongs to: Science Physics
Question #2
Convex lens forms virtual image when object is:
A. Within focal length
B. Beyond 2F
C. At 2F
D. Between F and 2F

Correct Answer: Option A


Explanation:
Convex lens: object within focal length (u < f) produces virtual, erect, magnified image (magnifying glass). Beyond F: real images. Memory tip: 'Convex lens: u < f ⇒ virtual image; u > f ⇒ real image'. Ray optics concept frequently tested in competitive exams to verify lens image formation rules.

This question belongs to: Science Physics
Question #3
A man walking at 5 km/h reaches his office 10 minutes late. If he walks at 6 km/h, he is 5 minutes early. Distance to office is
A. 5 km
B. 2.5 km
C. 10 km
D. 7.5 km

Correct Answer: Option D


Explanation:
Let distance d, usual time t hours. d/5 = t + 10/60, d/6 = t - 5/60. Subtract: d/5 - d/6 = (15/60) => d/30 = 0.25 => d = 7.5 km. Commonly asked.

This question belongs to: Science Physics