The frequency of a sound wave is 200 Hz. Its time period is
A. 0.005 s
B. 0.05 s
C. 200 s
D. 0.02 s
Answer: Option A
Solution (By JKSSB Mock Tests)
Time period T = 1/f = 1/200 = 0.005 s = 5 ms. Frequency is number of cycles per second. Relationship T = 1/f is fundamental. For 200 Hz, period is 5 milliseconds.
Explanation:
Electric potential V at a point is defined as work done per unit charge to bring a test charge from infinity to that point: V = W/q. Thus potential difference between two points is work per unit charge to move between them. Electric field intensity is force per unit charge; potential energy is work to assemble charges; capacitance is charge storage ability. Memory tip: 'Potential = work per unit charge; field = force per unit charge'. This definition-based question tests electrostatics fundamentals, frequently appearing in competitive exams. Always distinguish potential (scalar, work/charge) from field (vector, force/charge).
Explanation:
The area under the curve of a velocity-time graph represents the total displacement covered by an object in a given time interval. Since velocity = displacement/time, the product of velocity and time (the area) yields displacement. The slope of a velocity-time graph, conversely, represents acceleration.
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