The fundamental principle utilized in an optical endoscope, which allows doctors to examine the inside of the human body, is: MCQ with Answer and Explanation

The fundamental principle utilized in an optical endoscope, which allows doctors to examine the inside of the human body, is:
A. Diffraction of light
B. Scattering of light
C. Polarization of light
D. Total internal reflection of light
Answer: Option D
Solution (By JKSSB Mock Tests)
Endoscopes consist of bundles of flexible optical fibers. Light introduced at one end is trapped inside the fiber core because it repeatedly strikes the boundary at an angle greater than the critical angle. This Total Internal Reflection allows light and visual images to be transmitted through complex, curving paths inside the body.

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Practice More Physics Questions

Question #1
A bullet of mass 20 g fired from a gun of mass 5 kg with velocity 200 m/s. Recoil velocity of gun is
A. 0.4 m/s
B. 0.8 m/s
C. 1 m/s
D. 2 m/s

Correct Answer: Option B


Explanation:
Conservation of momentum: 0 = (0.02×200) + (5×v) => v = -4/5 = -0.8 m/s (magnitude 0.8 m/s).

This question belongs to: Science Physics
Question #2
The velocity-time graph of a particle moving in a straight line is shown. The displacement of the particle from t=0 to t=4s is: [Graph: triangle from (0,0) to (2,10) to (4,0)]
A. 20 m
B. 40 m
C. 30 m
D. 10 m

Correct Answer: Option A


Explanation:
Displacement = area under velocity-time graph. The graph forms a triangle with base 4 s and height 10 m/s. Area = ½ × base × height = ½ × 4 × 10 = 20 m. Since velocity is always positive, displacement equals distance travelled. Graphical analysis is powerful: area gives displacement, slope gives acceleration. This triangle represents motion with uniform acceleration followed by uniform retardation. Exam tip: For piecewise linear v-t graphs, calculate area of each geometric segment separately. Such graph-based questions assess conceptual clarity in motion analysis.

This question belongs to: Science Physics
Question #3
An echo returned in 0.5 s. If speed of sound is 340 m/s, the distance of reflecting surface is
A. 170 m
B. 85 m
C. 340 m
D. 680 m

Correct Answer: Option B


Explanation:
d = (v×t)/2 = (340×0.5)/2 = 170/2 = 85 m. Minimum distance for echo perception is about 17 m. Remember divide by 2 for one-way distance.

This question belongs to: Science Physics