The latent heat of fusion of ice is 80 cal/g. Heat required to melt 50 g ice at 0°C is MCQ with Answer and Explanation

The latent heat of fusion of ice is 80 cal/g. Heat required to melt 50 g ice at 0°C is
A. 800 cal
B. 4000 cal
C. 40 cal
D. 1600 cal
Answer: Option B
Solution (By JKSSB Mock Tests)
Q = mL = 50 × 80 = 4000 cal. (1 cal = 4.2 J, but here in cal). No temperature change during phase change. Latent heat of vaporization is 540 cal/g for water.

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