The material of a permanent magnet should have MCQ with Answer and Explanation

The material of a permanent magnet should have
A. Low retentivity, high coercivity
B. Low retentivity, low coercivity
C. High retentivity, high coercivity
D. High retentivity, low coercivity
Answer: Option C
Solution (By JKSSB Mock Tests)
Permanent magnets need high retentivity and high coercivity to stay magnetized. Steel, alnico.

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Practice More Physics Questions

Question #1
A 100 W bulb operates at 220 V. The current drawn by it is approximately:
A. 0.45 A
B. 2.2 A
C. 4.5 A
D. 0.22 A

Correct Answer: Option A


Explanation:
Electric power P = VI. Thus I = P/V = 100 W / 220 V ≈ 0.4545 A ≈ 0.45 A. This direct application of power formula is fundamental in electricity. Memory tip: 'I = P/V for resistive loads'. Competitive exams frequently test such calculations with household appliance ratings. Always use consistent units (watts, volts, amperes). Note: This assumes purely resistive load (valid for incandescent bulbs); for motors or electronics, power factor may matter, but not at this level.

This question belongs to: Science Physics
Question #2
Gravitational constant G dimensions:
A. [M⁰L⁰T⁰]
B. [ML³T⁻²]
C. [M⁻¹L²T⁻²]
D. [M⁻¹L³T⁻²]

Correct Answer: Option D


Explanation:
F = Gm₁m₂/r² ⇒ G = Fr²/(m₁m₂) = [MLT⁻²][L²]/[M²] = [M⁻¹L³T⁻²]. Memory aid: 'G dimensions: [M⁻¹L³T⁻²]; small value reflects weak gravity'. Dimensional analysis frequently tested in competitive exams.

This question belongs to: Science Physics
Question #3
The unit of latent heat of fusion is
A. J
B. J/kg
C. J/°C
D. W

Correct Answer: Option B


Explanation:
Latent heat per unit mass, Q = mL => L = Q/m, unit J/kg (or cal/g). Specific latent heat. Not per degree.

This question belongs to: Science Physics