The outer wheel of a cart makes 500 revolutions in moving a distance of 1.1 km. Find the diameter of the wheel. MCQ with Answer and Explanation

The outer wheel of a cart makes 500 revolutions in moving a distance of 1.1 km. Find the diameter of the wheel.
A. 50 cm
B. 35 cm
C. 70 cm
D. 105 cm
Answer: Option C
Solution (By JKSSB Mock Tests)
Distance in 1 revolution = Total distance / Number of revolutions = 1100 meters / 500 = 2.2 meters. Circumference = 2 * (22/7) * r = 2.2 meters => Diameter (2r) * (22/7) = 2.2 => Diameter = 2.2 * 7 / 22 = 0.7 meters = 70 cm.

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Practice More Time Speed and Distance Questions

Question #1
A train 220 meters long passes a signal post in 11 seconds. How long will it take to cross a platform 300 meters long?
A. 30 seconds
B. 26 seconds
C. 28 seconds
D. 24 seconds

Correct Answer: Option B


Explanation:
Speed of train = 220 / 11 = 20 m/s. Total distance to cross platform = 220 + 300 = 520 meters. Time taken = 520 / 20 = 26 seconds.

This question belongs to: Maths Time Speed and Distance
Question #2
A passenger train 140 meters long passes an active bridge platform 310 meters long in 20 seconds. What is the speed of the train in km/h?
A. 85 km/h
B. 90 km/h
C. 75 km/h
D. 81 km/h

Correct Answer: Option D


Explanation:
Total distance = 140 + 310 = 450 meters. Speed = 450 / 20 = 22.5 m/s. In km/h = 22.5 * (18/5) = 4.5 * 18 = 81 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3
A train passes a pedestrian standing on a platform in 8 seconds and passes the platform itself, which is 200 meters long, in 18 seconds. Find the speed of the train in km/h.
A. 72 km/h
B. 84 km/h
C. 80 km/h
D. 64 km/h

Correct Answer: Option A


Explanation:
Time taken to cross the platform alone = 18 - 8 = 10 seconds. Speed of train = 200 / 10 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.

This question belongs to: Maths Time Speed and Distance