The phenomenon of total internal reflection occurs when light travels from: MCQ with Answer and Explanation

Question
The phenomenon of total internal reflection occurs when light travels from:
A. Denser to rarer medium at angle less than critical angle
B. Denser to rarer medium at angle greater than critical angle
C. Rarer to denser medium
D. Any two media at any angle
Answer: Option B
Solution (By JKSSB Mock Tests)
Total internal reflection (TIR) requires: (1) light travels from denser to rarer medium (n₁ > n₂), and (2) angle of incidence exceeds critical angle θ_c = sin⁻¹(n₂/n₁). Option A describes refraction toward normal; B describes partial reflection/refraction; D is incorrect. Memory aid: 'TIR: denser→rarer AND i > θ_c'. This condition-based question tests optics fundamentals, frequently examined in competitive exams. Always verify both conditions for TIR; common applications include optical fibers and prisms in binoculars.
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Question #1
A ball is projected horizontally from top of a cliff. The time to hit ground depends on
A. Both velocity and height
B. Mass of ball
C. Height of cliff and g
D. Horizontal velocity
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Correct Answer: Option C

Explanation:
Vertical motion is independent of horizontal. t = √(2h/g). Mass doesn't affect. Horizontal velocity affects range, not time of fall. Projectile motion independence of perpendicular components.
This question belongs to: Science Physics
Question #2
What is the minimum distance required to hear a distinct echo? (Assuming speed of sound in air is 344 m/s)
A. 17.2 meters
B. 25.6 meters
C. 34.4 meters
D. 10 meters
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Correct Answer: Option A

Explanation:
The human ear retains the sensation of sound for about 0.1 seconds (persistence of hearing). To hear a distinct echo, the reflected sound must reach the ear after at least 0.1 s. Distance traveled by sound = Speed × Time = 344 m/s × 0.1 s = 34.4 m. Since this is the total distance (go and return), the minimum distance to the obstacle is 34.4 / 2 = 17.2 meters.
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Question #3
A 100 W bulb operates at 220 V. The current drawn by it is approximately:
A. 2.2 A
B. 4.5 A
C. 0.45 A
D. 0.22 A
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Correct Answer: Option C

Explanation:
Electric power P = VI. Thus I = P/V = 100 W / 220 V ≈ 0.4545 A ≈ 0.45 A. This direct application of power formula is fundamental in electricity. Memory tip: 'I = P/V for resistive loads'. Competitive exams frequently test such calculations with household appliance ratings. Always use consistent units (watts, volts, amperes). Note: This assumes purely resistive load (valid for incandescent bulbs); for motors or electronics, power factor may matter, but not at this level.
This question belongs to: Science Physics
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