The speed indices of two sprinters are in the ratio 3 : 4. If the first sprinter requires 24 seconds to wrap up a bend, how much time does the second sprinter require? MCQ with Answer and Explanation

The speed indices of two sprinters are in the ratio 3 : 4. If the first sprinter requires 24 seconds to wrap up a bend, how much time does the second sprinter require?
A. 22 seconds
B. 18 seconds
C. 16 seconds
D. 20 seconds
Answer: Option B
Solution (By JKSSB Mock Tests)
Ratio of speeds = 3:4, so ratio of times required = 4:3. Given 4 parts = 24 seconds => 1 part = 6 seconds. Time for the second sprinter = 3 parts = 3 * 6 = 18 seconds.

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Practice More Time Speed and Distance Questions

Question #1
A train 140 meters long passes a platform 160 meters long in 15 seconds. Find the speed of the train in km/h.
A. 60 km/h
B. 90 km/h
C. 80 km/h
D. 72 km/h

Correct Answer: Option D


Explanation:
Total distance = 140 + 160 = 300 meters. Speed = 300 / 15 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
A commuter drives to his consulting firm at 30 km/h and arrives 15 minutes late. If he increases his speed to 40 km/h, he arrives 5 minutes early. Find the distance to his firm.
A. 50 km
B. 40 km
C. 35 km
D. 45 km

Correct Answer: Option B


Explanation:
Time difference = 15 - (-5) = 20 minutes = 20/60 = 1/3 hours. Let distance be d. d/30 - d/40 = 1/3 => (4d - 3d)/120 = 1/3 => d/120 = 1/3 => d = 40 km.

This question belongs to: Maths Time Speed and Distance
Question #3
Walking at 6/7 of his normal pace, a man is 12 minutes late to his workplace. What is his normal time?
A. 64 minutes
B. 72 minutes
C. 80 minutes
D. 90 minutes

Correct Answer: Option B


Explanation:
New speed = 6/7 of normal pace => New time = 7/6 of normal time. Difference = 1/6 of normal time = 12 minutes. Normal time = 12 * 6 = 72 minutes.

This question belongs to: Maths Time Speed and Distance