The speed indices of two sprinters are in the ratio 3 : 4. If the first sprinter requires 24 seconds to wrap up a bend, how much time does the second sprinter require? MCQ with Answer and Explanation

The speed indices of two sprinters are in the ratio 3 : 4. If the first sprinter requires 24 seconds to wrap up a bend, how much time does the second sprinter require?
A. 20 seconds
B. 22 seconds
C. 18 seconds
D. 16 seconds
Answer: Option C
Solution (By JKSSB Mock Tests)
Ratio of speeds = 3:4, so ratio of times required = 4:3. Given 4 parts = 24 seconds => 1 part = 6 seconds. Time for the second sprinter = 3 parts = 3 * 6 = 18 seconds.

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Practice More Time Speed and Distance Questions

Question #1
Two trains 150 meters and 100 meters long are running along parallel tracks in the same direction at speeds of 56 km/h and 46 km/h respectively. In what time will the faster train cross the slower train completely?
A. 110 seconds
B. 100 seconds
C. 90 seconds
D. 80 seconds

Correct Answer: Option C


Explanation:
Total distance = 150 + 100 = 250 meters. Relative speed in same direction = 56 - 46 = 10 km/h = 10 * (5/18) = 25/9 m/s. Time required = 250 / (25/9) = 250 * 9 / 25 = 90 seconds.

This question belongs to: Maths Time Speed and Distance
Question #2
A train 150 meters long is running at 72 km/h. How long will it take to completely pass a platform of length 250 meters?
A. 25 seconds
B. 15 seconds
C. 20 seconds
D. 30 seconds

Correct Answer: Option C


Explanation:
Speed of train = 72 * (5/18) = 20 m/s. Total distance to cross platform = 150 + 250 = 400 meters. Time taken = 400 / 20 = 20 seconds.

This question belongs to: Maths Time Speed and Distance
Question #3
A man rows a boat 20 km downstream in 2 hours and returns upstream in 5 hours. Find the speed of the stream.
A. 3.0 km/h
B. 4.0 km/h
C. 3.5 km/h
D. 2.5 km/h

Correct Answer: Option A


Explanation:
Downstream speed = 20 / 2 = 10 km/h. Upstream speed = 20 / 5 = 4 km/h. Speed of stream = (10 - 4) / 2 = 6 / 2 = 3 km/h.

This question belongs to: Maths Time Speed and Distance