The speed of two runners are in the ratio 3 : 4. If the first runner takes 36 seconds to complete a loop, how much time does the second runner take? MCQ with Answer and Explanation

The speed of two runners are in the ratio 3 : 4. If the first runner takes 36 seconds to complete a loop, how much time does the second runner take?
A. 25 seconds
B. 30 seconds
C. 32 seconds
D. 27 seconds
Answer: Option D
Solution (By JKSSB Mock Tests)
Ratio of speeds = 3:4, so ratio of times taken = 4:3. Given 4 parts = 36 seconds => 1 part = 9 seconds. Time taken by the second runner = 3 parts = 3 * 9 = 27 seconds.

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Practice More Time Speed and Distance Questions

Question #1
An athlete runs a 200-meter race in 24 seconds. Find his speed in km/h.
A. 33.33 km/h
B. 28.5 km/h
C. 24 km/h
D. 30 km/h

Correct Answer: Option D


Explanation:
Speed in m/s = 200 / 24 = 25/3 m/s. To convert to km/h, multiply by 18/5. Speed = (25/3) * (18/5) = 5 * 6 = 30 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
A person wins a 100m race by completing it in 12 seconds. The runner-up takes 12.5 seconds. By how many meters did the winner beat the runner-up?
A. 6 meters
B. 5 meters
C. 8 meters
D. 4 meters

Correct Answer: Option B


Explanation:
Speed of runner-up = 100 / 12.5 = 8 m/s. When the winner crosses the finish line at 12 seconds, the distance covered by runner-up = 8 * 12 = 96 meters. Distance by which he lost = 100 - 96 = 5 meters.

This question belongs to: Maths Time Speed and Distance
Question #3
A car covered a distance of 400 km at a uniform speed. If the uniform speed index is lowered by 10 km/h, the journey takes 2 hours longer. Find the original speed.
A. 55 km/h
B. 45 km/h
C. 60 km/h
D. 50 km/h

Correct Answer: Option D


Explanation:
Let original speed be s. 400 / (s - 10) - 400 / s = 2 => 200 / (s - 10) - 200 / s = 1 => 2000 = s(s - 10). Solving s^2 - 10s - 2000 = 0 yields (s - 50)(s + 40) = 0. Original speed = 50 km/h.

This question belongs to: Maths Time Speed and Distance