The time period of a mass-spring system depends on MCQ with Answer and Explanation

The time period of a mass-spring system depends on
A. Gravity
B. Both mass and spring constant
C. Mass only
D. Spring constant only
Answer: Option B
Solution (By JKSSB Mock Tests)
T = 2π√(m/k). Depends on mass and stiffness.

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Practice More Physics Questions

Question #1
The material of permanent magnet is
A. Soft iron
B. Copper
C. Steel
D. Aluminium

Correct Answer: Option C


Explanation:
Steel has high retentivity, retains magnetism, used for permanent magnets. Soft iron has low retentivity, used for electromagnet core (temporary). Alnico, ferrites also used.

This question belongs to: Science Physics
Question #2
In a potentiometer, the sensitivity can be increased by:
A. Increasing the current in the primary circuit
B. Increasing the length of the wire
C. Decreasing the length of the wire
D. Using a thicker wire

Correct Answer: Option B


Explanation:
Potentiometer sensitivity (ability to detect small EMF changes) increases with longer wire because potential gradient (V/cm) decreases, allowing finer measurement of balancing length. Sensitivity ∝ length of wire. Decreasing length (B) reduces sensitivity; increasing current (C) increases potential gradient, reducing sensitivity; thicker wire (D) reduces resistance but doesn't directly affect sensitivity if current adjusted. Memory tip: 'Longer potentiometer wire ⇒ smaller potential gradient ⇒ higher sensitivity'. This experimental physics concept is frequently tested in competitive exams. Always link sensitivity to potential gradient: smaller gradient allows detection of smaller voltage differences.

This question belongs to: Science Physics
Question #3
A machine gun fires 60 bullets per minute, each of mass 10 g with velocity 600 m/s. The power developed by the gun is:
A. 300 W
B. 1800 W
C. 3000 W
D. 18000 W

Correct Answer: Option B


Explanation:
Power = work done per unit time = kinetic energy imparted per second. KE per bullet = ½mv² = ½×0.01×(600)² = 1800 J. Bullets per second = 60/60 = 1. Thus power = 1800 J/s = 1800 W. Note: Mass conversion: 10 g = 0.01 kg. This problem combines kinetic energy formula with power definition. Exam tip: Always convert to SI units first (grams to kg, minutes to seconds). Such numerical problems test multi-step calculation skills and unit conversion proficiency essential for competitive examinations.

This question belongs to: Science Physics