The time period of a simple pendulum is 2 s at a place where g=9.8 m/s². Its length is about MCQ with Answer and Explanation

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The time period of a simple pendulum is 2 s at a place where g=9.8 m/s². Its length is about

A. 0.5 m

B. 1 m

C. 0.25 m

D. 2 m

Answer: Option B

Solution (By JKSSB Mock Tests)

T=2π√(L/g) => L = gT²/(4π²) ≈ (9.8×4)/(4×9.87) ≈ 1 m.

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Correct Answer: Option C

Explanation:
Rules: leading zeros not significant; trailing zero after decimal is significant. Digits 4,0,5,0 are significant ⇒ 4 sig figs. Memory tip: 'Start at first non-zero; include trailing zeros after decimal'. Measurement precision concept frequently tested in competitive exams.

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