The time period of a simple pendulum on Earth is T. If taken to a planet where g is 4 times, new period is MCQ with Answer and Explanation

The time period of a simple pendulum on Earth is T. If taken to a planet where g is 4 times, new period is
A. 2T
B. T
C. T/4
D. T/2
Answer: Option D
Solution (By JKSSB Mock Tests)
T ∝ 1/√g, g'=4g => T' = T/√4 = T/2.

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An engine pumps water continuously through a hose. Water leaves the hose with a velocity 'v' and mass per unit length is 'm'. What is the power imparted to the water?
A. mv^3
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C. mv^2
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Correct Answer: Option D


Explanation:
Power is the rate of doing work or imparting kinetic energy (dK/dt). Mass exiting per second = m * v (mass/length * length/time). Kinetic energy imparted per second = 1/2 * (mass per second) * v^2 = 1/2 * (mv) * v^2 = 1/2 * m * v^3. This is a very common advanced mechanics question.

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Question #2
If the percentage error in measurement of radius of a sphere is 2%, the percentage error in volume is
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B. 2%
C. 8%
D. 4%

Correct Answer: Option A


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Correct Answer: Option A


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