The value of acceleration due to gravity g on the surface of Earth depends on MCQ with Answer and Explanation

The value of acceleration due to gravity g on the surface of Earth depends on
A. Shape of the object
B. Mass of the Earth
C. Rotation of the object
D. Mass of the object
Answer: Option B
Solution (By JKSSB Mock Tests)
g = GM/R², where M is mass of Earth, R radius, G universal constant. It does not depend on mass of falling object (Galileo's experiment). Earth's rotation causes slight variation but surface g is primarily determined by M and R. So mass of Earth is factor.

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Practice More Physics Questions

Question #1
What happens to the atomic number and mass number of a radioactive nucleus when it emits a gamma ray?
A. Atomic number increases by 1, mass number remains the same.
B. Both atomic number and mass number decrease by 1.
C. Both atomic number and mass number remain completely unchanged.
D. Atomic number decreases by 2, mass number decreases by 4.

Correct Answer: Option C


Explanation:
Gamma emission is the release of high-energy electromagnetic radiation (photons) from a nucleus transitioning from an excited high-energy state to a lower, stable energy state. Gamma rays carry no mass and no electrical charge. Therefore, the emission of a gamma ray does not alter the number of protons (atomic number) or the total number of nucleons (mass number) of the atom.

This question belongs to: Science Physics
Question #2
A body is projected with velocity u at angle θ to horizontal. The horizontal range is maximum when θ is:
A. 45°
B. 90°
C. 60°
D. 30°

Correct Answer: Option A


Explanation:
Horizontal range R = u²sin(2θ)/g. sin(2θ) is maximum (value 1) when 2θ = 90° ⇒ θ = 45°. Thus maximum range at 45° projection angle, assuming same initial speed and level ground. Memory tip: 'Max range at 45°; max height at 90°'. This standard projectile motion result is frequently tested in competitive exams. Always verify assumptions: no air resistance, uniform gravity, launch and landing at same height. For different heights, optimal angle differs.

This question belongs to: Science Physics
Question #3
The force of attraction between two bodies of masses 1 kg each separated by 1 m is (G=6.67×10⁻¹¹)
A. 6.67 × 10⁻¹¹ N
B. 6.67 × 10⁻⁹ N
C. 6.67 × 10⁻⁵ N
D. 6.67 × 10⁻⁷ N

Correct Answer: Option A


Explanation:
F = G×1×1/1² = 6.67×10⁻¹¹ N.

This question belongs to: Science Physics