The value of g at the centre of Earth is MCQ with Answer and Explanation

The value of g at the centre of Earth is
A. Zero
B. Infinite
C. 4.9 m/s²
D. 9.8 m/s²
Answer: Option A
Solution (By JKSSB Mock Tests)
g decreases with depth: g' = g(1 - d/R). At centre d=R, g'=0. Weightless at centre. At poles g=9.83, equator 9.78. At surface it's maximum.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Physics Questions

Question #1
A radioactive substance has half-life of 10 days. Fraction remaining after 30 days is
A. 1/16
B. 1/2
C. 1/8
D. 1/4

Correct Answer: Option C


Explanation:
Number of half-lives = 30/10 = 3. Remaining = (1/2)³ = 1/8. Exponential decay N = N₀(1/2)^(t/T). Radioactive decay constant λ = ln2/T.

This question belongs to: Science Physics
Question #2
The time period of a simple pendulum on Earth is T. If taken to a planet where g is 4 times, new period is
A. T/4
B. T/2
C. T
D. 2T

Correct Answer: Option B


Explanation:
T ∝ 1/√g, g'=4g => T' = T/√4 = T/2.

This question belongs to: Science Physics
Question #3
For an organ pipe completely closed at one end, the fundamental frequency is f. What are the frequencies of the next two higher harmonics?
A. 2f and 3f
B. 4f and 6f
C. 3f and 5f
D. 2f and 4f

Correct Answer: Option C


Explanation:
An organ pipe closed at one end features a node at the closed end and an antinode at the open end. Because of these boundary conditions, it can only support odd harmonics. If the fundamental frequency (1st harmonic) is f, the next permissible frequencies are the 3rd harmonic (3f), 5th harmonic (5f), 7th harmonic (7f), and so forth.

This question belongs to: Science Physics