The wavelength of visible light lies between MCQ with Answer and Explanation

The wavelength of visible light lies between
A. 1 nm - 10 nm
B. 1 mm - 10 mm
C. 400 nm - 700 nm
D. 700 nm - 1 mm
Answer: Option C
Solution (By JKSSB Mock Tests)
Visible spectrum approx 400 nm (violet) to 700 nm (red).

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Physics Questions

Question #1
If three resistors of 2 Ω, 3 Ω, and 6 Ω are connected in parallel, the equivalent resistance of the combination is:
A. 0.5 Ω
B. 2 Ω
C. 1 Ω
D. 11 Ω

Correct Answer: Option C


Explanation:
For resistors in parallel, the reciprocal of the equivalent resistance (1/Rp) is the sum of the reciprocals of individual resistances. 1/Rp = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/6. Finding a common denominator (6): 1/Rp = 3/6 + 2/6 + 1/6 = 6/6 = 1. Therefore, Rp = 1 Ω.

This question belongs to: Science Physics
Question #2
The color of sky is blue due to
A. Reflection
B. Dispersion
C. Refraction
D. Scattering

Correct Answer: Option D


Explanation:
Rayleigh scattering of sunlight by air molecules, blue scattered most.

This question belongs to: Science Physics
Question #3
A wire of resistance 9 Ω is bent to form an equilateral triangle. The resistance across any two vertices is
A. 6 Ω
B. 9 Ω
C. 2 Ω
D. 3 Ω

Correct Answer: Option C


Explanation:
Total 9 Ω, each side 3 Ω. Across two vertices, one side is 3 Ω in parallel with series of two sides (3+3=6 Ω). Equivalent: (3×6)/(3+6) = 18/9 = 2 Ω. Triangle resistance network.

This question belongs to: Science Physics