Three forces in equilibrium: if two are equal and at 120°, third force is: MCQ with Answer and Explanation

Three forces in equilibrium: if two are equal and at 120°, third force is:
A. Zero
B. Difference of two
C. Sum of two
D. Equal to each, at 120° to both
Answer: Option D
Solution (By JKSSB Mock Tests)
Vector equilibrium: three equal forces at 120° form closed triangle. Third force equals magnitude of others, oriented 120° from each. Memory aid: 'Equilibrium: vector sum = 0; symmetric forces ⇒ symmetric angles'. Statics concept frequently tested in competitive exams.

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Practice More Physics Questions

Question #1
Which of the following statements is correct for an object moving with constant speed?
A. Its displacement equals distance
B. It may have acceleration
C. Its velocity is constant
D. It must have zero acceleration

Correct Answer: Option B


Explanation:
Constant speed does not imply zero acceleration if direction changes, e.g., uniform circular motion has centripetal acceleration. Velocity may change direction. Displacement magnitude ≤ distance. So only option B is correct.

This question belongs to: Science Physics
Question #2
Electric motor works on principle of:
A. Electromagnetic induction
B. Force on current in magnetic field
C. Thermal expansion
D. Electrostatic attraction

Correct Answer: Option B


Explanation:
Motor: current-carrying conductor in magnetic field experiences Lorentz force (F = ILB), causing rotation. Generator uses reverse principle (induction). Memory tip: 'Motor: electricity ⇒ motion (force); Generator: motion ⇒ electricity (induction)'. Device principle question frequently tested in competitive electromagnetism sections.

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Question #3
The gravitational force between two objects of masses 2 kg and 3 kg separated by 2 m (G = 6.67×10⁻¹¹) is
A. 1×10⁻¹⁰ N
B. 2×10⁻¹⁰ N
C. 1.0005×10⁻¹⁰ N
D. 6.67×10⁻¹¹ N

Correct Answer: Option C


Explanation:
F = G m1 m2 / r² = 6.67×10⁻¹¹ × 6 / 4 = 6.67×10⁻¹¹ × 1.5 = 1.0005×10⁻¹⁰ N.

This question belongs to: Science Physics