Two numbers are in ratio 11:6. Their difference is 42. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 11:6. Their difference is 42. What is their sum?

A. 263

B. 560

C. 633

D. 527

Answer: Option D

Solution (By JKSSB Mock Tests)

Numbers 11k, 6k. Difference |11-6|k = 42 ⇒ k = 8. Sum = (11+6)k ≈ 527.

This question belongs to: Maths Ratio and Proportion

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Question #1

Two numbers are in ratio 6:4. Their difference is 103. What is their sum?

A. 558

B. 617

C. 250

D. 500

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Correct Answer: Option D

Explanation:
Numbers 6k, 4k. Difference |6-4|k = 103 ⇒ k = 51. Sum = (6+4)k ≈ 500.

This question belongs to: Maths Ratio and Proportion

Question #2

Ratio of present ages of A and B is 3:5. After 6 years, the ratio becomes 4:7. Present age of A is?

A. 68 years

B. 58 years

C. 126 years

D. 63 years

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Correct Answer: Option D

Explanation:
Let ages 3k and 5k. Then (3k + 6)/(5k + 6) = 4/7. Solving gives k ≈ 21, age of A = 3*21 = 63.

This question belongs to: Maths Ratio and Proportion

Question #3

If a:b = 7:7 and b:c = 7:9, then a:b:c = ?

A. 7:8:9

B. 14:14:18

C. 7:7:9

D. 6:7:10

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Correct Answer: Option C

Explanation:
Combine ratios: a:b = 7:7, b:c = 7:9 ⇒ a:b:c = 7:7:9.

This question belongs to: Maths Ratio and Proportion

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