Two numbers are in ratio 11:7. Their difference is 58. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 11:7. Their difference is 58. What is their sum?

A. 280

B. 126

C. 350

D. 252

Answer: Option D

Solution (By JKSSB Mock Tests)

Numbers 11k, 7k. Difference |11-7|k = 58 ⇒ k = 14. Sum = (11+7)k ≈ 252.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1

Two numbers are in the ratio 11:13 and their sum is 148. Find the numbers.

A. 96 and 67

B. 132 and 156

C. 50 and 90

D. 66 and 78

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Correct Answer: Option D

Explanation:
Numbers = 11k and 13k. 11k + 13k = 148 ⇒ k = 6. Thus, numbers are 66 and 78.

This question belongs to: Maths Ratio and Proportion

Question #2

If a:b = 8:3 and b:c = 3:6, then a:b:c = ?

A. 8:4:6

B. 7:3:7

C. 16:6:12

D. 8:3:6

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Correct Answer: Option D

Explanation:
Combine ratios: a:b = 8:3, b:c = 3:6 ⇒ a:b:c = 8:3:6.

This question belongs to: Maths Ratio and Proportion

Question #3

If a:b = 8:8 and b:c = 8:10, then a:b:c = ?

A. 16:16:20

B. 7:8:11

C. 8:8:10

D. 8:9:10

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Correct Answer: Option C

Explanation:
Combine ratios: a:b = 8:8, b:c = 8:10 ⇒ a:b:c = 8:8:10.

This question belongs to: Maths Ratio and Proportion

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