Two numbers are in ratio 7:10. Their difference is 99. What is their sum? MCQ with Answer and Explanation

Two numbers are in ratio 7:10. Their difference is 99. What is their sum?
A. 546
B. 482
C. 229
D. 459
Answer: Option D
Solution (By JKSSB Mock Tests)
Numbers 7k, 10k. Difference |7-10|k = 99 ⇒ k = 33. Sum = (7+10)k ≈ 459.

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Practice More Ratio and Proportion Questions

Question #1
Ratio of present ages of A and B is 7:5. After 10 years, the ratio becomes 8:8. Present age of A is?
A. 266 years
B. 133 years
C. 138 years
D. 127 years

Correct Answer: Option B


Explanation:
Let ages 7k and 5k. Then (7k + 10)/(5k + 10) = 8/8. Solving gives k ≈ 19, age of A = 7*19 = 133.

This question belongs to: Maths Ratio and Proportion
Question #2
Two numbers are in the ratio 13:5 and their sum is 464. Find the numbers.
A. 341 and 114
B. 325 and 125
C. 314 and 136
D. 650 and 250

Correct Answer: Option B


Explanation:
Numbers = 13k and 5k. 13k + 5k = 464 ⇒ k = 25. Thus, numbers are 325 and 125.

This question belongs to: Maths Ratio and Proportion
Question #3
Two numbers are in ratio 11:5. Their difference is 105. What is their sum?
A. 160
B. 320
C. 368
D. 414

Correct Answer: Option B


Explanation:
Numbers 11k, 5k. Difference |11-5|k = 105 ⇒ k = 17. Sum = (11+5)k ≈ 320.

This question belongs to: Maths Ratio and Proportion