Two numbers are in ratio 7:12. Their difference is 121. What is their sum? MCQ with Answer and Explanation

Question

Share Report Error

Two numbers are in ratio 7:12. Their difference is 121. What is their sum?

A. 326

B. 218

C. 190

D. 95

Answer: Option C

Solution (By JKSSB Mock Tests)

Numbers 7k, 12k. Difference |7-12|k = 121 ⇒ k = 24. Sum = (7+12)k ≈ 190.

This question belongs to: Maths Ratio and Proportion

Request complete Subject PDF

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Ratio and Proportion Questions

Question #1

Two numbers are in ratio 7:4. Their difference is 73. What is their sum?

A. 297

B. 594

C. 636

D. 734

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option B

Explanation:
Numbers 7k, 4k. Difference |7-4|k = 73 ⇒ k = 24. Sum = (7+4)k ≈ 594.

This question belongs to: Maths Ratio and Proportion

Question #2

If a:b = 7:7 and b:c = 7:6, then a:b:c = ?

A. 6:7:7

B. 7:8:6

C. 14:14:12

D. 7:7:6

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option D

Explanation:
Combine ratios: a:b = 7:7, b:c = 7:6 ⇒ a:b:c = 7:7:6.

This question belongs to: Maths Ratio and Proportion

Question #3

Find the mean proportional between 16 and 72.

A. 66

B. 36

C. 33

D. 88

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option C

Explanation:
Mean proportional = √(16 × 72) = √(1152) = 33.

This question belongs to: Maths Ratio and Proportion

Explore All Ratio and Proportion MCQs