Two numbers are in ratio 9:4. Their difference is 40. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 9:4. Their difference is 40. What is their sum?

A. 572

B. 714

C. 286

D. 601

Answer: Option A

Solution (By JKSSB Mock Tests)

Numbers 9k, 4k. Difference |9-4|k = 40 ⇒ k = 8. Sum = (9+4)k ≈ 572.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1

If a:b = 5:5 and b:c = 5:8, then a:b:c = ?

A. 5:5:8

B. 4:5:9

C. 10:10:16

D. 5:6:8

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Correct Answer: Option A

Explanation:
Combine ratios: a:b = 5:5, b:c = 5:8 ⇒ a:b:c = 5:5:8.

This question belongs to: Maths Ratio and Proportion

Question #2

Ratio of present ages of A and B is 4:8. After 10 years, the ratio becomes 5:9. Present age of A is?

A. 93 years

B. 96 years

C. 101 years

D. 192 years

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Correct Answer: Option B

Explanation:
Let ages 4k and 8k. Then (4k + 10)/(8k + 10) = 5/9. Solving gives k ≈ 24, age of A = 4*24 = 96.

This question belongs to: Maths Ratio and Proportion

Question #3

If a:b = 3:10 and b:c = 10:8, then a:b:c = ?

A. 3:11:8

B. 6:20:16

C. 2:10:9

D. 3:10:8

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Correct Answer: Option D

Explanation:
Combine ratios: a:b = 3:10, b:c = 10:8 ⇒ a:b:c = 3:10:8.

This question belongs to: Maths Ratio and Proportion

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