Walking at 5/6 of his normal pace, a man is 10 minutes late to his workplace. What is his normal time? MCQ with Answer and Explanation

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Walking at 5/6 of his normal pace, a man is 10 minutes late to his workplace. What is his normal time?

A. 60 minutes

B. 50 minutes

C. 55 minutes

D. 45 minutes

Answer: Option B

Solution (By JKSSB Mock Tests)

New speed = 5/6 of normal pace => New time = 6/5 of normal time. Difference = 1/5 of normal time = 10 minutes. Normal time = 10 * 5 = 50 minutes.

This question belongs to: Maths Time Speed and Distance

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Question #1

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A car ascends an incline path 24 km long at 6 km/h and maps the return path descent at 12 km/h. Find the net average speed for the round course.

A. 9.6 km/h

B. 7.2 km/h

C. 8.8 km/h

D. 8.0 km/h

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Correct Answer: Option D

Explanation:
Average Speed = 2xy / (x + y) = (2 * 6 * 12) / (6 + 12) = 144 / 18 = 8 km/h.

This question belongs to: Maths Time Speed and Distance

Question #2

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A train 120 meters long passes a telegraph post in 8 seconds. How long will it take to pass a platform 240 meters long?

A. 28 seconds

B. 24 seconds

C. 20 seconds

D. 32 seconds

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Correct Answer: Option B

Explanation:
Speed of train = 120 / 8 = 15 m/s. Total distance to pass platform = 120 + 240 = 360 meters. Time taken = 360 / 15 = 24 seconds.

This question belongs to: Maths Time Speed and Distance

Question #3

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A walk at 5/6 of usual speed makes a person 10 minutes late. What is his usual time?

A. 60 minutes

B. 40 minutes

C. 50 minutes

D. 70 minutes

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Correct Answer: Option C

Explanation:
New Speed = 5/6 of usual speed => New Time = 6/5 of usual time. Difference = 1/5 * Usual Time = 10 minutes => Usual Time = 50 minutes.

This question belongs to: Maths Time Speed and Distance

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