Walking at 5/7 of his usual speed, a man reaches his destination 24 minutes late. What is his usual time? MCQ with Answer and Explanation

Walking at 5/7 of his usual speed, a man reaches his destination 24 minutes late. What is his usual time?
A. 50 minutes
B. 70 minutes
C. 80 minutes
D. 60 minutes
Answer: Option D
Solution (By JKSSB Mock Tests)
New speed = 5/7 of usual speed => New time = 7/5 of usual time. Difference = 2/5 of usual time = 24 minutes. 1/5 of usual time = 12 minutes => Usual time = 60 minutes.

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Practice More Time Speed and Distance Questions

Question #1
A thief is spotted by a policeman from a distance of 250 meters. The thief runs at 11 km/h and the policeman chases him at 13 km/h. Find the distance covered by the thief before he is caught.
A. 1375 meters
B. 1625 meters
C. 1500 meters
D. 1250 meters

Correct Answer: Option A


Explanation:
Relative speed = 13 - 11 = 2 km/h. Time to catch the thief = 0.25 km / 2 km/h = 0.125 hours. Distance covered by thief = Speed * Time = 11 km/h * 0.125 hours = 1.375 km = 1375 meters.

This question belongs to: Maths Time Speed and Distance
Question #2
A train traveling at 60 km/h overtakes a motor cyclist riding at 12 km/h in the same direction in 12 seconds. Find the length of the train.
A. 160 meters
B. 200 meters
C. 180 meters
D. 140 meters

Correct Answer: Option A


Explanation:
Relative speed = 60 - 12 = 48 km/h = 48 * (5/18) = 40/3 m/s. Length of train = Relative speed * Time = (40/3) * 12 = 160 meters.

This question belongs to: Maths Time Speed and Distance
Question #3
A cyclist tracks 1200 meters in exactly 4 minutes. Find his speed index in km/h.
A. 22 km/h
B. 20 km/h
C. 15 km/h
D. 18 km/h

Correct Answer: Option D


Explanation:
Time = 4 minutes = 240 seconds. Speed = 1200 / 240 = 5 m/s. In km/h = 5 * (18/5) = 18 km/h.

This question belongs to: Maths Time Speed and Distance