Walking at 7/9 of his baseline typical speed, a courier agent reaches his office terminal 12 minutes late. Find his typical baseline time parameter. MCQ with Answer and Explanation
Walking at 7/9 of his baseline typical speed, a courier agent reaches his office terminal 12 minutes late. Find his typical baseline time parameter.
A. 42 minutes
B. 38 minutes
C. 46 minutes
D. 50 minutes
Answer: Option A
Solution (By JKSSB Mock Tests)
New speed = 7/9 of usual speed => New time = 9/7 of usual time. Difference = 2/7 of usual time = 12 minutes. 1/7 of usual time = 6 minutes => Usual time = 42 minutes.
Explanation:
Speed of B = 600 / 75 = 8 m/s. Distance covered by B when A crosses the finish line at 66 seconds = 8 * 66 = 528 meters. Winning margin = 600 - 528 = 72 meters.
Explanation:
Relative speed = 125 / 10 = 12.5 m/s = 12.5 * (18/5) = 45 km/h. Since they are in the same direction: Relative Speed = Speed of train - Speed of man => 45 = Speed of train - 5 => Speed of train = 50 km/h.
Two trains 120 meters and 130 meters long are running in opposite directions at speeds of 45 km/h and 45 km/h respectively. In what time will they cross each other?
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