What is the equivalent capacitance when three capacitors of 3 microfarads each are connected in series?
A. 0.33 microfarads
B. 3 microfarads
C. 1 microfarad
D. 9 microfarads
Answer: Option C
Solution (By JKSSB Mock Tests)
The formula for capacitors in series is exactly the opposite of resistors. 1/C_eq = 1/C1 + 1/C2 + 1/C3. Here, all are 3 uF. So, 1/C_eq = 1/3 + 1/3 + 1/3 = 3/3 = 1. Therefore, C_eq = 1 microfarad. When identical capacitors are in series, you simply divide the capacitance by the number of capacitors (3/3 = 1).
Explanation:
Angular momentum (L = mvr) has dimensions [ML²T⁻¹]. Planck's constant (h = E/ν) also has dimensions [ML²T⁻¹]. They share the same dimensional formula. Force is [MLT⁻²], Power is [ML²T⁻³], Momentum is [MLT⁻¹], and Strain is a dimensionless quantity [M⁰L⁰T⁰]. This is a frequent exam question.
Explanation:
I_rms defined so I_rms²R = average power, same heating as DC current. For sine wave: I_rms = I₀/√2. Memory tip: 'RMS: heating equivalence; use RMS for power calculations'. AC fundamentals frequently tested in competitive exams.
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