What is the equivalent capacitance when three capacitors of 3 microfarads each are connected in series?
A. 0.33 microfarads
B. 1 microfarad
C. 3 microfarads
D. 9 microfarads
Answer: Option B
Solution (By JKSSB Mock Tests)
The formula for capacitors in series is exactly the opposite of resistors. 1/C_eq = 1/C1 + 1/C2 + 1/C3. Here, all are 3 uF. So, 1/C_eq = 1/3 + 1/3 + 1/3 = 3/3 = 1. Therefore, C_eq = 1 microfarad. When identical capacitors are in series, you simply divide the capacitance by the number of capacitors (3/3 = 1).
Explanation:
F = m×a. New force F' = (2m)×(a/2) = m×a = F. So force remains unchanged. This is direct proportionality. Understand the relationship: doubling mass doubles force, halving acceleration halves it, net effect no change.
Explanation:
EM waves transverse: E ⊥ B ⊥ propagation direction. Derived from Maxwell's equations. Memory tip: 'EM wave: right-hand rule for E×B direction'. Wave property frequently tested in competitive modern physics sections.
Explanation:
Astigmatism: cornea curvature not spherical, different focal lengths in different planes. Corrected by cylindrical lens which has different powers in perpendicular axes. Not simple spherical lens.
No comments yet. Be the first to start the discussion!