Which of the following is an application of electromagnetic induction? MCQ with Answer and Explanation

Which of the following is an application of electromagnetic induction?
A. Electric bell
B. Moving coil galvanometer
C. Electric fuse
D. Dynamo
Answer: Option D
Solution (By JKSSB Mock Tests)
Dynamo/generator converts mechanical to electrical energy using induction.

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Practice More Physics Questions

Question #1
The work done by a conservative force in moving a particle along a closed path is:
A. Positive
B. Depends on path
C. Zero
D. Negative

Correct Answer: Option C


Explanation:
Conservative forces (gravity, spring, electrostatic) have path-independent work; work done over any closed loop is zero. This defines conservative forces and enables potential energy definition. Non-conservative forces (friction) have non-zero closed-path work. Memory aid: 'Conservative force: ∮F·dr = 0; enables energy conservation'. This mechanics concept is frequently tested in competitive exams. Always link conservative forces to potential energy and mechanical energy conservation; this is foundational for advanced physics problem-solving.

This question belongs to: Science Physics
Question #2
A ball is dropped from a height 'h' and simultaneously another ball is thrown horizontally from the same height. Which ball will hit the ground first? (Neglect air resistance)
A. The dropped ball
B. Depends on the initial horizontal velocity
C. The horizontally thrown ball
D. Both will hit the ground simultaneously

Correct Answer: Option D


Explanation:
Vertical and horizontal motions are completely independent. Both balls have zero initial downward (vertical) velocity and both are subject to the same downward acceleration due to gravity (g). Since the vertical height (h) is the same, using h = ut + ½gt², time t = √(2h/g) applies equally to both. Thus, they hit the ground simultaneously.

This question belongs to: Science Physics
Question #3
A vernier caliper has 20 divisions on vernier scale matching 19 main scale divisions. If main scale division is 1 mm, least count is:
A. 0.5 mm
B. 0.05 mm
C. 0.01 mm
D. 0.1 mm

Correct Answer: Option B


Explanation:
Least count = 1 MSD - 1 VSD. 20 VSD = 19 MSD ⇒ 1 VSD = 19/20 mm = 0.95 mm. LC = 1 - 0.95 = 0.05 mm. Formula: LC = MSD/n where n = vernier divisions. Memory tip: LC = smallest measurable difference = main scale value/vernier divisions. Essential for practical physics questions in competitive exams.

This question belongs to: Science Physics