A and B can do a piece of work in 12 days, B and C in 15 days, and C and A in 20 days. In how many days will A, B, and C finish it working together? MCQ with Answer and Explanation

Explanation:
Let efficiency of B = 1, then efficiency of A = 2. Combined efficiency = 3 units/day. Total work = 8 * 3 = 24 units. Time taken by A alone = 24 / 2 = 12 days.

Explanation:
Combined rate = 1/19 + 1/19. Required time = 9.5 days.

Explanation:
Total work = LCM(12, 15, 20) = 60 units. Efficiency of (A+B) = 5, (B+C) = 4, (C+A) = 3. Summing efficiencies gives 2*(A+B+C) = 12 => Efficiency of (A+B+C) = 6 units/day. Efficiency of A = (A+B+C) - (B+C) = 6 - 4 = 2 units/day. Time taken by A alone = 60 / 2 = 30 days.