Explanation:
Let efficiency of C = 1, then B = 2 and A = 4. Combined efficiency = 1 + 2 + 4 = 7 units/day. Total work = 4 * 7 = 28 units. Time taken by C alone = 28 / 1 = 28 days.
If 8 men and 12 boys can finish a piece of work in 10 days, while 6 men and 8 boys can finish it in 14 days, find the time taken by 1 man alone to complete the work.
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